e^x+y=sin(xy)两边同时对x进行求导，得：e^x+y'=cos(xy)*(y+xy')∴[xcos(xy)-1]y'=e^x-ycos(xy)∴y'=[e^x-ycos(xy)]/[xcos(xy)-1]望采纳
e^x+1=cos(xy)(y+xy')y'=(e^x+1)/cos(xy)x-y/x
