LGJ-95的导线最多能承受的电流是多大?计算公式是怎么算的
有2个网友回答
LGJ-95是截面为95平方毫米的钢芯铝绞线。其正常温度下(气温25℃、导线度70℃)载流量为335A,在35KV的供电线路中,其最大的负荷功率为:S=1.732*335A*35000V=20.31MVA。当然,这是计算得出的,实际使用当中,它能带的负荷肯定比这要小得多,因为需要考虑的因数很多,比如:线路输送距离,电压降,等等……………….
这个没有计算公式,裸导线做成了,载流量就固定了给你个表,希望对你有所帮助钢芯铝绞线长期允许载流量(A)导 线 型 号最 高 允 许 温 度(℃) +70 +80LGJ-10
LGJ-16
LGJ-25
LGJ-35
LGJ-50
LGJ-70
LGJ-95
LGJ-120
LGJ-150
LGJ-185
LGJ-240
LGJ-300
LGJ-400
LGJQ-150
LGJQ-185
LGJQ-240
LGJQ-300
LGJQ-300(1)
LGJQ-400 80
105 108
130 138
175 183
210 215
265 260
330 352
380 401
445 452
510 631
610 613
690 755
835 840
450 435
505 518
605 651
690 708
721
825 836
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