帮忙计算一下这个环形变压器多少功率

2024年12月04日 23:10
有4个网友回答
网友(1):

铁芯截面宽=130/2-48/2=41毫米。
铁芯截面积=41*80=32.8平方厘米。
查铁芯截面积与容量关系曲线图,在33平方厘米处,变压器容量为700VA。

网友(2):

环形变压器的功率计算同E型或F型的计算方法是一样的,只是环形变压器的磁通密度可以取得高一些,假设磁通密度为10000高斯,则计算公式:AC=1.2√P
AC是铁芯截面积:单位:cm² P是变压器功率:单位:VA
AC=(13-4.8)/2×8=32cm²
P=(AC/1.2)²=(32/1.2)²=746VA

网友(3):

铁芯的截面大小和导磁率决定了它最大可以做多大的变压器。
铁心内径48mm 外径130mm 高80mm
横截面积=[(130-48)/2]*80=3280(M㎡)=32.8(c㎡)
现今的硅钢片的导磁率一般在10000高斯付近,取10000高斯,按经验公式
变压器铁芯横截面积:S=1.25×根号P
所以P=(32.8/1.25)平方≈688(W)

网友(4):

输出功率?这个取决与负载的大小!匝数越多越烧不了,当然越粗越好!不过实际情况是短路都烧不了,因为线圈的电阻,即使短路输出电流也就那大,如果长期短路肯定会把电源烧了!

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