分解因式x4+y4+(x+y)4-2

2024年11月22日 05:14
有1个网友回答
网友(1):

x4+y4+(x+y)4-2=(x2+y2)2-2x2y2+(x+y)4-2
=[(x+y)2-2xy]2-2x2y2+(x+y)4-2
=(x+y)4-4xy(x+y)2+4x2y2-2x2y2+(x+y)4-2
=2(x+y)4-4xy(x+y)2+2x2y2-2
=2[(x+y)4-2xy(x+y)2+x2y2]-2
=2[(x+y)2-xy]2-2
=2[x2+y2+xy]2-2=2(x2+y2+xy+1)(x2+y2+xy-1)