二重积分计算一道,希望有过程,谢谢

2025年03月01日 12:15
有1个网友回答
网友(1):

I = ∫<0, π/2>dx∫<0, 2>xycos(xy^2)dy
= (1/2)∫<0, π/2>dx∫<0, 2>cos(xy^2)d(xy^2)
= (1/2)∫<0, π/2>dx[sin(xy^2)]<0, 2>
= (1/2)∫<0, π/2>sin4xdx = -(1/8)[cos4x]<0, π/2> = 1/8