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概率论与数理统计 参数估计 一致性（相合性）
概率论与数理统计 参数估计 一致性（相合性）
为什么(u估)是u的一致估计，就可以得到(u估)^2是u^2的一致估计?
2025年03月15日 11:53
有1个网友回答
网友（1）：
因为y=u^2是连续函数，所以是相合估计。
这里有定理保证，可以看茆诗松的概率论与数理统计教程第六章第二节定理2.
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