求解一道数学题

2024-10-31 05:38:39
有1个网友回答
网友(1):

y=f(cosx)
dy/dx
= d/dx f(cosx)
=d/dcosx f(cosx) . d/dx (cosx) ; 链式法则
= f'(cosx) . (-sinx)
/
I
=∫(0->π) f(cosx) cosx dx -∫(0->π) f'(cosx) (sinx)^2 dx
=∫(0->π) f(cosx) cosx dx +∫(0->π) sinx.[f(cosx)]' dx