如图为大肠杆菌的DNA分子结构示意图(片段).请据图回答问题:(1)图中1表示______,2表示______,1、2

2025年04月06日 23:11
有1个网友回答
网友(1):

(1)由图可知,1是磷酸、2是脱氧核糖,1、2、3结合在一志的结构叫脱氧核苷酸,遗传信息储存在碱基的排列顺序中.
(2)DNA分子中,A与T之间有两个氢键,C与G之间有三个氢键,图中有三个氢键,所以3是鸟嘌呤或胞嘧啶.
(3)设含有腺嘌呤x个,则T有x个,C=G,有100-x个,所以A-T之间的氢键为2x,C-G之间的氢键有3×(100-x),根据题意,氢键共有260个,所以2x+3×(100-x)=260,求得x=40个,所以胞嘧啶数为60个,复制4次,增加15个DNA分子,故需要原料胞嘧啶脱氧核苷酸15×60=900个.
(4)只含14N的DNA的相对分子质量为a,所以含有14N的每条链相对分子质量为

a
2
,只含15N的DNA的相对分子质量为b,所以含有15N的每条链相对分子质量为
b
2
,将只含15N的DNA培养到含14N的培养基中,根据半保留复制原则,子一代DNA分子中一条是14N链,一条是15N链,所以子一代DNA的平均相对分子质量为
a+b
2
.子二代共有4个DNA分子,含有15N的链为2条,含有14N链为6条,所以总相对分子质量为b+3a,故每个DNA的平均相对分子质量为
3a+b
4

故答案为:
(1)磷酸    脱氧核糖     脱氧核苷酸    遗传信息
(2)2 鸟嘌呤、胞嘧啶
(3)40    900
(4)
a+b
2
 
3a+b
4

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