http://zhidao.baidu.com/question/333697368.html
x = fminimax(fun,x0)给定初值x0, 求函数最小值;
x = fminimax(fun,x0,A,b)给定初值x0,且满足A x<=b,A是矩阵,b是向量;
x = fminimax(fun,x,A,b,Aeq,beq),满足A x<=b,满足线性方程组Aeq*x = beq;Aeq矩阵,beq向量;
x = fminimax(fun,x,A,b,Aeq,beq,lb,ub),用法同上,再满足 lb<=x<=ub;
x = fminimax(fun,x0,A,b,Aeq,beq,lb,ub,nonlcon) subjects the minimax problem to the nonlinear inequalities c(x) or equality constraints ceq(x) defined in nonlcon. fminimax optimizes such that c(x) ≤ 0 and ceq(x) = 0. Set lb = [] and/or ub = [] if no bounds exist.
[x,fval] = fminimax(...)返回最小值时x值和函数最小值。
[x,fval,maxfval] = fminimax(...) 返回目标函数最大值;
[x,fval,maxfval,exitflag] = fminimax(...)返回 exitflag描述最小值存在状态。
希望帮上你。