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好吧问答库 > 7.5KW1440转的电机配180比1的减速机能吊起多重的物件

7.5KW1440转的电机配180比1的减速机能吊起多重的物件

2025年04月07日 10:10

有3个网友回答

网友（1）：

T=9550*P*I*η/n1
T表示扭矩 P输入功率 I减速比 η传动效率 n1输入转速
T=9550*7.5*180*η/1440=8953.125n.m
g=9.8n/kg
所以： T=913.5842kg.m

网友（2）：

914Kg.m

网友（3）：

O(∩_∩)O哈哈~ 可以花张图给咱传过来看啊看

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