解不等式:①x-1⼀2(4x-1)<3⼀2 ②{(4+x)⼀2}+1≥4(x+1)⼀3

2024年11月30日 01:34
有2个网友回答
网友(1):

x-1/2(4x-1)<3/2
2x-(4x-1)<3
2x-4x+1<3
2x>-2
x>-1

{(4+x)/2}+1≥4(x+1)/3
3(4+x)+6≥8(x+1)
12+3x+6≥8x+8
5x≤10
x≤2

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网友(2):

:①x-1/2(4x-1)<3/2
x-2x+1/2<3/2;
-x<1;
x>-1;
②{(4+x)/2}+1≥4(x+1)/3;
12+3x+6≥8x+8;
5x≤10;
x≤2