C语言冒泡排序法

2025年03月24日 19:01
有5个网友回答
网友(1):

#include //链接标准头文件
#define N 5 //定义常量N并赋值为5
void main() //主函数入口
{ //表示主函数开始
int i,j; //定义整形变量i和j
int grade[N],temp; //定义N维(N=5,也就是五维啦^^)整形数组和整形变量temp
printf("输入5个数\n"); //在屏幕上显式“输入5个数”并且换行
for(i=0;i{ //循环体开始
scanf("%d",&grade[i]); //依次获取用户输入的整数值并存入数组grade中
} //循环结束
for(i=0;i{ //外层循环体开始
for(j=0;j{ //内层循环体开始
if(grade[j]{ //如果整形数组前面的数比其后的小,执行以下语句
temp=grade[j+1]; //将比较大的数赋值给temp
grade[j+1]=grade[j]; //将比较小的数赋值给数组中后面的变量
grade[j]=temp; //将比较大的数赋值给数组中前面的变量
} //从此便完成大小变量的交换,使得大值往前放
} //结束内层循环
} //结外内层循环,完成排序
printf("最后排序为:\n");//在屏幕显式“最后排序为:”并换行
for(i=0;i{ //开始循环输出
printf("%d",grade[i]); //只是这里要逐个输出数组中的五个数值
} //结束循环输出
printf("\n"); //输出换行到屏幕,看不到什么效果,可删掉
} //结束main()函数

网友(2):

进来了就说下吧,C语言冒泡排序法的基本思想是:将相邻的数据元素的关键字进行比较,若前面元素的关键字大于后面元素的关键字,则将它们互换,否则不交换!
例如下面从小到大排序的源程序:
#include
#define n 5
void main(){
int i,j,temp;
int a[] = {20,45,10,43,19};
printf("未排序的数组是:\n");
for(i = 0;i < n;i++)
{
printf("%3d ",a[i]);
}
for(i = 0;i{
for(j = i+1;j{
if(a[i] < a[j])
{
temp = a[j];
a[j] = a[i];
a[i] = temp;
}
}
}
printf("\n排序后的数组是:\n");
for(i = 0; i < n;i++){
printf("%d ",a[i]);
}
printf("\n");
}

网友(3):

#include
void main()
{
int a[]={4,2,3,1},i,j;
int temp;
for (i=0;i<4;i++)
{ for(j=0;j<4-i;j++)
{
if(a[j]>a[j+1])
{
temp=a[j];
a[j]=a[j+1];
a[j+1]=temp;
} printf("%d",a[j]);
}printf("\n");
}
printf("\n");
printf("最后排列出的结果为:");
for(j=0;j<4;j++)
{
printf("%d",a[j]);
}
putchar('\n');

}
两个相邻的数进行比较,较小的数在前面较大的数往后排
(从小到大排列)执行完一次又重新排,直到所有的数都是从小到大为此,方才结束.

网友(4):

有n个数,进行n便过滤 第i遍时从第1个数起到第n-i个数止
依次比较x 和 x+1两个数 如果数(x)〉(x+1)就交换他们
形象一些就好象是将较大的数向下沉,每一遍都会把这一遍能遇到的
最大数压倒底,这样n便之后,就形成了小到大的有序数列

网友(5):

想了解的话,找本C语言书看吧,有这方面的例题。

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