用因式分解法简化计算 已知:x+y=1,xy=-1⼀2 求:x(x+y)(x-y)-x(x+y)^2的值

2024年11月23日 03:27
有3个网友回答
网友(1):

x(x+y)(x-y)-x(x+y)^2
=x(x+y)(x-y-x-y)
=-2xy(x+y) x+y=1,xy=-1/2
=-2*(-1/2)*1
=1

网友(2):

x(x+y)(x-y)-x(x+y)^2
=x(x+y)[(x-y)-(x+y)]
=x(x+y)(x-y-x-y)
=-2xy(x+y)
=-2×(-1/2)×1
=1

网友(3):

x(x+y)(x-y)-x(x+y)^2
=x(x+y)[(x-y)-(x+y)]
=x(x+y)(x-y-x-y)
=-2xy(x+y)
=-2*(-1/2)*1
=1