由题意知x≥1√[x+2√(x-1)]+√[x-2√(x-1)]=√[√(x-1)+1]²+√[√(x-1)-1]²当x＞2时原式=[√(x-1)+1]+[√(x-1)-1]=2√(x-1)当1≤x≤2时原式=[√(x-1)+1]+[1-√(x-1)]=2
