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好吧问答库 > 求大神帮忙解一下这道题。

求大神帮忙解一下这道题。

2024年12月07日 08:13

有1个网友回答

网友（1）：

电容放电，最后电压=电阻分压。
最初2s
uc=qc/C
dqc/dt=ic=Cduc/dt
ic=（u-uc）/R1= Cduc/dt
duc/（u-uc）=dt/R1C
-ln（u-uc）=t/R1C十D1
ln（u-uc）= -t/R1C-D1
u-uc=D2e^（-t/R1C）
uc=u- D2e^（-t/R1C）
t=0,uc=0，D2=u

uc=u- ue^（-t/R1C）
t=2,uc（2）= u- ue^（-2/R1C）
ic=(u-uc)/R1
= ue^（-t/R1C）/R1
ic（0）=u/R1，
ic（2）= ue^（-2/R1C）/R1

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