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好吧问答库 > 若（3m-2)x的2次方乘y的n+1是xy的系数为-5的8次单项式，求m,n ?

若（3m-2)x的2次方乘y的n+1是xy的系数为-5的8次单项式，求m,n ?

2025年04月08日 08:47

有2个网友回答

网友（1）：

解，因为是xy的8次单项式，所以有x的次数加上y的次数和为8
即：2+(n+1)=8
解得：n=5
其次系数为-5
所以有3m-2=-5
解得m=-1

网友（2）：

单项式的次数是所有字母的指数之和，所以2+（n+1）=8，解得n=5
单项式的系数是单项式中数字因数，所以3m-2=-5，所以m=-1

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