C语言 定义一个复数结构,求两个复数的和与积

刚学习也 呵呵 写的不细致。
忽忽~ 我错咯~ 我自己看书，半个月，还没看到那去，肯定写搞笑咯，我表示的只是一个形式，非真正的复数也～ 算咯，摆那我也不删它咯。


你可以不用函数，自己改了就行。





/**



* Generate the sum and product of two plural numbers.



*/



#include







struct pluralNum {



float x; float y;};







int main(void)



{



struct pluralNum p1, p2;



struct pluralNum getPluralNum(void);



void calSum(struct pluralNum a, struct pluralNum b);



void calProduct(struct pluralNum a, struct pluralNum b);







p1 = getPluralNum();



p2 = getPluralNum();







calSum(p1, p2);



calProduct(p1, p2);







printf("Thank You!\n");



return 0;



}











struct pluralNum getPluralNum(void)



{



struct pluralNum temp;



static int count = 1;







printf("Please specify the plural number.\n");



printf("real number: x = ");



scanf("%f", &temp.x);



printf("imaginary number: y = ");



scanf("%f", &temp.y);







printf("You specified the plural number p%i =:\n", count);



printf("%.2f+%.2fi\n", temp.x, temp.y);



count++;





return (temp);



}











void calSum(struct pluralNum a, struct pluralNum b)



{







printf("The sum of p1 and p2 is:\n");



printf("%.2f+%.2fi\n", a.x + b.x, a.y + b.y);



}











void calProduct(struct pluralNum a, struct pluralNum b)



{



float realNum, imaginaryNum;







realNum = a.x * b.x - a.y * b.y;



imaginaryNum = a.x * b.y + b.x * a.y;







printf("The product of p1 and p2 is:\n");



printf("%.2f+%.2fi\n", realNum, imaginaryNum);



}

struct { int x, int y };