灯泡L1电阻R1= U P1 = (6V)2 3W =12Ω,灯泡L2电阻R2= U P2 = (12V)2 3W =48Ω,电路电流为I= U R1+R2 = 15V 12Ω+48Ω =0.25A,灯泡L1的实际功率P3=I2R1=(0.25A)2×12Ω=0.75W<3W,不能正常发光.灯泡L2的实际功率P4=I2R2=(0.25A)2×48Ω=3W=3W,所以能正常发光.故选B.