计算(1⼀x+1⼀y)÷(1⼀x^2-1⼀y^2)

2024年11月30日 05:52
有3个网友回答
网友(1):

(1/x+1/y)÷(1/x^2-1/y^2)
= (x+y)/(xy) ÷ (y^2-x^2)/(x^2y^2)
= (x+y)/(xy) * (x^2y^2)/(y^2-x^2)
= (x+y)/(xy) * (xy)^2/{-(x+y)(x-y)}
= -xy/(x-y)

网友(2):

(1/x+1/y)÷(1/x^2-1/y^2)
=(1/x+1/y)÷[(1/x+1/y)(1/x-1/y)]
=1÷(1/x-1/y)
=1÷[(y-x)/xy]
=xy/(y-x)

网友(3):

xy/(y-x)