1.已知sin(π⼀4-α)=3⼀5,π⼀4-α为第二象限角,求sin(α-13π⼀4)+sin(α+21π⼀4)的值

2.已知y=a-bcos(3x-π/2的最大值为6,最小值为-2,求实数a,b的值
2024年11月18日 10:26
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1
sin(π/4-α)=3/5
π/4-α为第二象限角
cos(π/4-α)=-根号[1-sin^2(π/4-α)]=-根号[1-(3/5)^2] = -4/5
sin(α-13π/4)+sin(α+21π/4)
=sin(-4π+π+α-π/4)+sin(4π+π+α+π/4)
=sin(π+α-π/4)+sin(π+α+π/4)
=-sin(α-π/4)-sin(α+π/4)
=sin(π/4-α)-cos(π/2-α-π/4)
=sin(π/4-α)-cos(π/4-α)
=3/5-(-4/5)
=8/5

2.
y=a-bcos(3x-π/2)
-1≤ cos(3x-π/2) ≤ 1

当b>0时:
最小值a-b=-2,最大值a+b=6
a=2,b=4

当b<0时:
最小值a+b=-2,最大值a-b=6
a=2,b=-4