x=g(y)是f(x)=lnx+arctanx的反函数求g'(π/4)解:∵ x=g(y)是f(x)=lnx+arctanx的反函数;∴ g'(y)=1/f'(x)=1/[(1/x)+1/(1+x²)]=x(1+x²)/(x²+x+1).........①x=1时,y=f(1)=ln1+arctan1=0+π/4=π/4; 将x=1代入①式即得:g'(π/4)=2/3;
g'(π/4)=1/f'(π/4)f'(x)=1/x+1/(x²+1)