计算:(1)(-3xy2)3?(16x3y)2;(2)4a2x2?(-25a4x3y3)÷(-12a5xy2);(3)(2x-y)(4x2-y2)

2024年11月23日 01:16
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(1)(-3xy23?(

1
6
x3y)2
=-27x3y6?
1
36
x6y2
=-
3
4
x9y8

(2)4a2x2?(-
2
5
a4x3y3)÷(-
1
2
a5xy2),
=4a2x2?(-
2
5
)a4x3y3÷(-
1
2
)a5xy2
=
16
5
ax4y;

(3)(2x-y)(4x2-y2)(2x+y),
=(4x2-y2)(4x2-y2),
=(4x2-y)2
=16x4-8x2y2+y4

(4)x2?(x+2)(x?2)?(x+
1
x
)2

=x2-x2+4-x2-2-
1
x2

=-x2+2-
1
x2