设A=2X^2-3XY+Y^2-X+2Y, B=4X^2-6XY+2Y^2-3X-Y, 若|X

-2a|+(Y+3)^2=0, 且B-2A=a,求A的值
2024-11-07 23:55:17
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|x+2a|+(y+3)^2=0
x=-2a,y=-3

B-2A=a
a=4x^2-6xy+2y^2-3x-y-2(2x^2-3xy+y^2-x+2y)

=4x^2-6xy+2y^2-3x-y-4x^2+6xy-2y^2+2x-4y
=-x-5y

|x-2a|
=|x-2(-x-5y)|

=|x+2x+10y|
=|3x+10y|
=|3x-30|
=0
解得x=10

A=2x^2-3xy+y^2-x+2y
=(x-y)(2x-y)-x+2y
=13×23-10-6
=283