|x+2a|+(y+3)^2=0x=-2a,y=-3B-2A=aa=4x^2-6xy+2y^2-3x-y-2(2x^2-3xy+y^2-x+2y)=4x^2-6xy+2y^2-3x-y-4x^2+6xy-2y^2+2x-4y=-x-5y|x-2a|=|x-2(-x-5y)|=|x+2x+10y|=|3x+10y|=|3x-30|=0解得x=10A=2x^2-3xy+y^2-x+2y=(x-y)(2x-y)-x+2y=13×23-10-6=283