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sin方x+cos方x=1sinx+cosx=1/5怎么解? 解得结果是多少?
2025年03月16日 09:51
有5个网友回答
网友(1):

1、由sinx+cosx=1/5=0.2得
sinx=0.2-cosx
2、将sinx=0.2-cosx代入sin方x+cos方x=1,可得
(0.2-cosx)²+cos²x=1,解方程得
cosx=0.8或cosx=-0.6 将结果代入sinx=0.2-cosx,解得
sinx=-0.6或sinx=0.8
因此x的值为第四象限或为第二象限。

网友(2):

把下面的等式两边平方 就可以得到 sinxcosx=-12/25
在根据sinx+cosx=1/5 就可以得到结果
因为正炫与余炫函数值相反 所以 在二四象限
所以为 sinx=-3/5 cosx=4/5
或则是

网友(3):

sinx+cosx=1/5 (1)
sin^2x+cos^2x=1 (2)
将(1)^2-(2)得
2sinxcosx=-24/25
(sinx-cosx)^2=(sinx+cosx)^2-4sinxcosx=49/25
即:sinx-cosx=7/5 (3) 或sinx-cosx=-7/5 (4)
联立(1)、(3)解得sinx=4/5,cosx=-3/5
联立(1)、(4)解得sinx=-3/5,cosx=4/5

网友(4):

(sinx+cosx)²=1/25
sin²x+cos²x+2sinxcosx=1/25
1+2sinxcosx=1/25
sinxcosx=-12/25
sinx+cosx=1/5
由韦达定理
sinx和cosx是方程x²-x/5-12/25=0的根
(x-4/5)(x+3/5)=0
x=4/5,x=-3/5
所以sinx=4/5,cosx=-3/5
sinx=-3/5,cosx=4/5

网友(5):

由sinx+cosx=1/5
得:sinx=1/5-cosx,
代入sin方x+cos方x=1
得:(5cosx+3)(5cosx-4)=0
所以:cosx=-3/5,sinx=4/5或cosx=4/5,sinx=-3/5

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