|x+1/x-1|(x-1)+(x-1)/(x-1)>0 2x/(x-1)>0 x(x-1)>0 即x>1或x<0 2. x+1/x-1<1 (x+1)/(x-1)-1<0 (x+1)/(x-1)-(x-1)/(x-1)<0 2/(x-1)<0 (x-1)<0 x<1 所以取 x<0 解集是:{x|x<0,x∈R}
