两数相除,商是28,余数是7,除数是几?当除数最小,被除数是几?

2025年04月07日 05:11
有1个网友回答
网友(1):

设a是被除数,b是除数,则a=28b+7.(b>7)
这是一个函数式,有无穷多答案。
比如b=8,那么a=28×8+7=231;
再如b=8.5,那么a=28×8.5+7=245;
如此等等。
除数没有最小。若b≦7,余数就不再是7.
比如b=7,则a=28×7+7=29×7=203,余数是0;
若b=6,则a=28×6+7=28×6+6+1=29×6+1=175,余数是1.
若规定除数和被除数都要是正整数,则除数有最小值,其最小值是8;

此时被除数a也有最小值231.

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