t눀+t-1=0 (2)x눀+9x=0 (3)5x눀+2x-3=0 (4)-x눀+6x+7=0 配方法步骤?

2024-10-30 21:27:53
有2个网友回答
网友(1):

(1)t²+t-1=0
t²+t=1
t²+t+1/4=1+1/4
(t+1/2)²=5/4
t+1/2=±√5/2
t=-1/2±√5/2
(2)x²+9x=0
x²+9x+(9/2)²=81/4
(x+9/2)²=81/4
x+9/2=±9/2
x=-9/2±9/2
x1=0
x2=-9
(3)5x²+2x-3=0
5x²+2x=3
x²+2x/5=3/5
x²+2x/5+(1/5)²=15/25+1/25
(x+1/5)²=16/25

x+1/5=±4/5
x=-1/5±4/5
(4)-x²+6x+7=0
x²-6x=7

x²-6x+9=7+9
(x-3)²=16
x-3=±4
x=3±4
x1=7
x2=-1

网友(2):

(1)t²+t+1/4=5/4
(t+1/2)²=5/4
t=-1/2±√5/2
(2)(x+9/2)²=(9/2)²
x=-9/2±9/2
x=0或-9
(3)x²+2x/5=3/5
(x+1/5)²=1/25+3/5
(x+1/5)²=16/25
x=-1/5±4/5
x=-1或3/5
(4)x²-6x-7=0
(x-3)²=16
x=3±4
x=7或-1